Recently, I have been working on hydrolysis of an ester to acid and am facing a problem.
Aromatic Compound A (with an ester , R-COOCH3) is dissolved in (methanol+water+NaOH solution, methanol is being used for solution homogeneity) and heated to reflux and maintained at reflux for 3-5 hours. I understand that R-COONa and CH3OH are formed by this basic hydrolysis and this reaction is a one-way reaction(since NaOH is being used) Please correct me if i am wrong with the chemistry. The mass is then cooled and pH is adjusted to 2.5-3.0 with 20% H2SO4 solution at amibient temperature to form R-COOH which is isolated by filtration. Analysis of the isolated product shows 40% R-COOCH3 and 60% R-COOH
Can some one help me to understand where the R-COOH to R-COOCH3 conversion is occuring. Does esterification of R-COOH with the methanol that is already present in the solution occur at ambient temperature. Does diluted (20% H2SO4 )acid catalyse to favour this reaction?
Regds/Bharathi