Ok, I came up with something, And i Feel pretty good about it
Here it is
(1st) C(s) + H2O(g) = CO(g) + H2(g) ΔH°=131.3 kJ/mol
I found out the ΔH° from the Δ
fH° values in the book
-this reaction absorbs 131.3 kJ/mol (endothermic)
(2nd) C(s) + O2(g) = CO2(g) ΔH°= -393.5 kJ/mol
I came up with this equation and just used the book value for CO2(g)
NOW
Since 1000g of carbon is really 83.257 mols of C
My reasoning:
The (1st equation) requires 131.3 Kj/ 1 mol of C(s)
to convert 1Kg of C to water gas we need 83.257 mols of C = 10931.644 Kj of energy to be absorbed
And for 1 mol of C to convert into 1 mol of CO2(g) -393.5 Kj are released for each mole of C(s) [according to the 2nd equation]
So if the reaction take 10931.644 kJ, then divide that by -393.5 kJ/mol
this will equal the number of mols of C(s) required to burn.
=27.7805 mols of C(s) required to convert 1 kg of c(s) to water gas.
so take those moles and convert them in to g
=2.31 g C
Is this right?
Ok I was just informed 2.31 g is not the right answer,
Any more suggestions, where did i go wrong?