More confusing then helpfull.
As you have alredy solved the question, at least show sci0x that it is the same equation.
Apologies. I assumed he had covered both equations in class already. To get the second form of the equation, you first take the ln of both sides.
(1) ln k
1 = ln A + (-E
a1/R)(1/T)
(2) ln k
2 = ln A + (-E
a2/R)(1/T)
Now, noting that A is equal in both equations, substracting (2) from (1) gives the second form of the Arrhenius equation