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Topic: Help w/ reaction problem  (Read 4104 times)

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Offline Dynamo22

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Help w/ reaction problem
« on: November 21, 2012, 05:33:16 PM »
I'm not looking for the answer straight out, I just wanted some help. I've always had trouble remembering the ring opening reagents, mechanisms, etc. Any tips on how to start to solve this one?

Edit*: The available reagents in the drop boxes are: H2/Pt, O3 then Zn/H2O, CH3MgBr then H3O+, O3 then H2O2, H3PO4 and heat, and CH3CO3H then H2O.

Offline sjb

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Re: Help w/ reaction problem
« Reply #1 on: November 22, 2012, 02:34:19 AM »
Can you work backwards, perhaps? How can you make the keto ester?

Offline orgopete

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Re: Help w/ reaction problem
« Reply #2 on: November 22, 2012, 03:52:58 AM »
Hint, I think reagent 3 is the O3 then H2O2.
Author of a multi-tiered example based workbook for learning organic chemistry mechanisms.

Offline zhangcarlin

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Re: Help w/ reaction problem
« Reply #3 on: November 22, 2012, 09:00:55 AM »
Hint, I think reagent 3 is the O3 then H2O2.
And then CH3CO3H then H2O

Offline orgopete

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Re: Help w/ reaction problem
« Reply #4 on: November 22, 2012, 09:28:52 AM »
Author of a multi-tiered example based workbook for learning organic chemistry mechanisms.

Offline zhangcarlin

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Re: Help w/ reaction problem
« Reply #5 on: November 22, 2012, 09:41:11 AM »
Hint, I think reagent 3 is the O3 then H2O2.
And then CH3CO3H then H2O
Why?
Oxidation the aldehyde to carboxylic acid

Offline orgopete

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Re: Help w/ reaction problem
« Reply #6 on: November 22, 2012, 10:16:17 AM »
There were two different ozonization procedures, one with a reductive work up and one with an oxidative work up. I suggested the oxidative work up. An oxidative work up converts aldehydes to acids.
Author of a multi-tiered example based workbook for learning organic chemistry mechanisms.

Offline Dynamo22

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Re: Help w/ reaction problem
« Reply #7 on: November 23, 2012, 10:27:18 PM »
Hey guys, sorry for taking so long to get back to you, holidays got a hold of me. Thanks for the hints, I got it figured out. Did the Grignard, reduced the 2° alcohol to alkene, then used the CH3CO3H to get the resultant product. Checked out just fine.

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