analyte : 0.2M NH
4OH
20mL
titrant : 0.1M HCl
Calculate the concentration of NH
4OH(or NH
3) in solution at equivalent point.
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I used
0.2M × 20mL = 0.1M × xmL
x=40mL
its initial concentration is 0.2M
its initial volume is 20mL
its final volume is 20+40mL = 60mL
So NH
4OH 's concentration is
0.2M × (20mL/60mL)
=0.2/3
=0.06
7M
is this right?
I don't know how to calculate this..
help me..