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How do you actually work out these thermochemical equations?
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Topic: How do you actually work out these thermochemical equations? (Read 4956 times)
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Munch
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How do you actually work out these thermochemical equations?
«
on:
January 16, 2006, 06:58:32 AM »
Hi - i'm a chemistry beginner and finding enthalpy and gas laws just so hard
Can someone please help with write the following thermochemical equations that relate to the following enthalpy changes
CH3OH(l) = -715kJmol-1 - which i think is C(s) + 2H2(g) + 1/2O2
CH3COCH3(l) = -216kJmol-1 - which i think is 3C + 3H2 + 1/2O2
but the problem one is
(NH4)3*PO4(s) = -1681kJmol-1
How do you actually work out these thermochemical equations. Do you have to break them down into their componants?
Thanks so much for any help
«
Last Edit: January 16, 2006, 03:28:29 PM by Mitch
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plu
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Re:Thermochemical equations
«
Reply #1 on:
January 16, 2006, 07:23:31 AM »
I believe you are talking about enthalpies of
formation
. In that case, your first two equations are correct. For the third, simply break the compound down into its basic elements like you did for the first two and add them
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Munch
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Re:Thermochemical equations
«
Reply #2 on:
January 16, 2006, 07:33:41 AM »
Add what though? thats the problem i dont understand.
(NH4)3*PO4(s)
2N2 + 3H2 + P + 2O2
When i look at the table for the standard entahlpys of formation they are all 0!!
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plu
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Re:Thermochemical equations
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Reply #3 on:
January 16, 2006, 01:08:34 PM »
You just wrote the equation! I do not see what the problem is...
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How do you actually work out these thermochemical equations?