[Pranav]

Also, dialdehyde is not given as an answer in any of the options given with this question.

Can you post the options given with the question?

The options are:
a. Cyclohexanone
b. Cyclopentanone
c. Cyclohexanol
d. Hexane-1,2-dicarboxylicacid.

[discodermolide]

The only thing it can be is d, Hexane-1,2-dicarboxylicacid.

[orgopete]

In that case, I think cyclopentanone could be the product.

This would be my thinking. Because ozone is the second step, then elimination must be occurring (if NaNH2/NH3 were the reagent, this would seem more plausible, none the less). Ozone formally gives a dialdehyde plus H2O2. H2O2 plus an aldehyde gives an aldehyde acid (plus some diacid). If BaO were not present, then the diacid seems plausible, but it would form a salt with barium. No aldol products are listed so it cannot be an aldol product of the dialdehyde. An intramolecular Claisen of the enolate of the aldehyde could give 2-oxocyclopentanecarboxaldehyde. A retro-Claisen by attack upon the aldehyde could liberate Formica acid and give the enolate of cyclopentanone. Tautomerization and neutralization would give te ketone. Just guessing.