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Topic: Enthalpy of neutralisation  (Read 1386 times)

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Offline DVilla7

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Enthalpy of neutralisation
« on: February 23, 2013, 12:49:28 PM »
Hi friends of chemicalforums i would just like to check if I am going about a calculation the correct way. I am trying to work out the heat evolved during the reaction at 25 °C:

H2SO4 + 2NaOH  :rarrow: Na2SO4 + 2H2O

Am i right in thinking that it would be [(2* ΔHΘf of H2O) + ( ΔHΘf of Na2SO4)] - [(2* ΔHΘf of H2SO4) + (ΔHΘf of NaOH)] ?

Also would this give me the enthalpy of reaction per kmol of H2SO4?

So if i was only reacting 0.1253kmol of Acid would i times the value calculated previously by 0.1253? Another thing is I am confused which ΔHΘf of Na2SO4 i should use as i can only find it for crystals, but it will be aqeous in my reactor when it is formed.

Thanks guys would really appreciate any help

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