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Topic: a ceramic contains 23 mol% MgO and the rest silicon dioxide  (Read 3467 times)

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98offroadZR2

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a ceramic contains 23 mol% MgO and the rest silicon dioxide
« on: January 25, 2006, 07:08:20 PM »
what is the wt% MgO in the ceramic, what is the mol% Si in the ceramic, what is the O/Si ratio in mol/mol in the ceramic


How do i go about solving this
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Offline Bakegaku

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Re:a ceramic contains 23 mol% MgO and the rest silicon dioxide
« Reply #1 on: January 27, 2006, 10:19:56 PM »
To find the weight percentage of MgO, you'd look up the molar mass of MgO and then multiply that by the percentage of MgO moles in the ceramic.  (converting percentage into a decimal, of course)  Do the same for SiO, add the numbers, then divide the number you got for MgO by the sum of the two numbers.
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