Amide NH2- is not stable in aqueous solutions. In water you will find NH4+ , CO32-, HCO3-, OH- and Na+.
Hi Hunter2 thanks for the reply.
Hmm, I'm having a lot of trouble understanding the mechanism in these reactions. For example, when NH
4+ reacts with OH
- from my book I assume that the more acidic substance will force the less acidic substance to act as a base and the way to determine which substance is more acidic is to look at which atom the hydrogen atom is bonded too (that is the most important factor for acidity in my book), so looking at the 2 substances, oxygen being more electronegative than nitrogen I would guess that the OH
- ion is more acidic than the NH
4+ ion. But that's not true as in this acid base reaction NH
4+ gives up its proton to the OH
- to form ammonia and water. So what's wrong with my concept?
Also, I'm not very sure what to do if the spectator ions were given to me. In the ammonium and hydroxide ion case, if the spectator ions were given I would be able to tell they they would get cancelled out in the products due to my secondary school education. However, I was told that in higher levels of education I should use the mechanism to deduce the products of my reaction. So in such reactions, how should i tell which are the spectator ions in a reaction?
I'm quite worried about this because it seems like I can't really understand the mechanisms in the acid-base reaction which according to the book should be very simple to understand..
Thanks so much for the help