[biomed77]

a person's blood sugar level is usually around 100mg per 100cm^3. if this level falls below 60mg per 100cm^3, insulin can occur. the desity of blood is 1.2cm^-3
what is the percentage by mass of sugar in the blood
i)when the blood sugar level is normal??
ii)during insulin shock??

what is the molar concentration of sugar C6H12O6, in the blood
i)under normal conditions??
ii)during insulin shock??

i solved this problem saing that.. W1 / W1 + W2 x 100
where W1 = mass of solute, W2 = mass of solvent
W1 = 100mg   W2 = volume of blood  x  density of blood = 100 x 1.2 = 120mg
mass % = 100 / 100 + 120 x 100 = 83.33%  thats the mass of sugar when normal

when insulin shock = mass % = 60 / 60 + 120 = 60 / 180 x 100 = 33.33%

can someone please tell me if i am doing it right? if not where is my mistake?? i talked with my mates at uni and they have different results, can someone confirm that it is wrong??? thanks

[Borek]

First of all - your results are obviously wrong without any analysis of your calculations. 80% concentration is like you take a glass, fill it up in 4/5 with sugar and fill up with water. This is syrup, not anything bloodlike.

1g = 1000mg

http://www.chembuddy.com/?left=concentration&right=mass-percentage

What is mass of the 100mL of solution with 1.2 g/mL density?

http://www.chembuddy.com/?left=concentration&right=percentage-to-molarity

[biomed77]

you are right borek but unfortunatelly i dont understand it!!!!!!!!
of course its surup....silly me!

[biomed77]

mass = volume x density
= 100 x 0.0012
= 0.12g

so under normal conditions we have 0.100g of glucose in 0.12g of blood

so percentage of mass under these conditions is ( mass of glucose / total mass)
0.100g / 0.12g = 0.83

during insulin shock:
0.006 / 0.12= 0.05

i know that is wrong again so can someone please guide me on this one???

i really need to finish this exersice by tonight.   thanks

[Borek]

mass = volume x density
= 100 x 0.0012
= 0.12g

No. Pay attention to units.