You've got 4 aromatic protons that are equal 2/2, that is an obvious sign of an aromatic ring disustituted in para orientation.
The only other proton is a width singlet about ~4.7ppm, that must be OH (that agrees with the 63ÂșC melting point, you definetly need hydrogen bonds, stronger than NH ones).
You absolutely need to have para-X-phenol
where X can't be easily identified.
Don't you have mass spectra??
It must be totally clarifier, you will get something like this:
(Molecular ion +2 with aprox. the same abundance than molecular ion, since we know bromine 79 and 81 isotopes are both about 50% abundance).
I vote for this:
But I'm afraid you won't be able to tell exactly which must be the other substitutent just with 1H NMR shifts.