Predict the relative heights of the peaks at M, M+2, and M+4 of CH2BrCl. I know how to do this if it were two halogens atoms that are of the same identity (binomial expansion), so how do you do this if the halogen atoms are not the same?
You can write out all the possible combinations of Br/Cl isotopes and scale the peaks to the relative abundance:
e.g. if we say
79Br:
81Br is 0.5:0.5 and
35Cl:
37Cl is 0.75:0.25, it follows that:
79Br:
81Br:
35Cl:
37Cl is 50:50:0.75:0.25
In the molecule CH
2BrCl, there are only 4 combinations. Write them out and use the ratio of the isotopes to work out the ratio of the peaks. This is thinking in terms of probability, i.e. the probability of getting
79Br
35Cl is 0.5 x 0.75 = 0.375. Repeat for every combination and you have the ratio of the peaks.
Another question, why is chloramphenicol's M/M+2/M+4 ratio not 9:6:1?
Who says it's not? Based on the Cl alone it should be 9:6:1 as far as I can see.