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Topic: Mass Spec with two different halogens?  (Read 13040 times)

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Offline Sophia7X

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Mass Spec with two different halogens?
« on: March 28, 2013, 10:19:25 PM »
How would you do this?

Predict the relative heights of the peaks at M, M+2, and M+4 of CH2BrCl. I know how to do this if it were two halogens atoms that are of the same identity (binomial expansion), so how do you do this if the halogen atoms are not the same?


Another question, why is chloramphenicol's M/M+2/M+4 ratio not 9:6:1?
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Offline Arkcon

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Re: Mass Spec with two different halogens?
« Reply #1 on: March 29, 2013, 08:12:41 AM »
Another question, why is chloramphenicol's M/M+2/M+4 ratio not 9:6:1?

Let's start with this one.  Why should it be?  And why would it not be?  Consider: does nitrophenol have a perfect ratio?  Is there something special about chlorine's isotope distribution?  Then you can try part 1.
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Offline Altered State

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Re: Mass Spec with two different halogens?
« Reply #2 on: March 29, 2013, 08:16:32 AM »
This is what I have from my lectures, guess it may help


Offline Dan

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Re: Mass Spec with two different halogens?
« Reply #3 on: March 29, 2013, 11:19:29 AM »
Predict the relative heights of the peaks at M, M+2, and M+4 of CH2BrCl. I know how to do this if it were two halogens atoms that are of the same identity (binomial expansion), so how do you do this if the halogen atoms are not the same?

You can write out all the possible combinations of Br/Cl isotopes and scale the peaks to the relative abundance:

e.g. if we say 79Br:81Br is 0.5:0.5 and 35Cl:37Cl is 0.75:0.25, it follows that:

79Br:81Br:35Cl:37Cl is 50:50:0.75:0.25

In the molecule CH2BrCl, there are only 4 combinations. Write them out and use the ratio of the isotopes to work out the ratio of the peaks. This is thinking in terms of probability, i.e. the probability of getting 79Br35Cl is 0.5 x 0.75 = 0.375. Repeat for every combination and you have the ratio of the peaks.

Quote
Another question, why is chloramphenicol's M/M+2/M+4 ratio not 9:6:1?

Who says it's not? Based on the Cl alone it should be 9:6:1 as far as I can see.
« Last Edit: March 31, 2013, 02:48:52 PM by Dan »
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Offline Sophia7X

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Re: Mass Spec with two different halogens?
« Reply #4 on: March 31, 2013, 02:27:26 PM »
Thanks Dan.

For the chloramphenicol problem, my solutions manual says this:





I don't understand why the M+2 peak is so close to the M peak.
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Offline Dan

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Re: Mass Spec with two different halogens?
« Reply #5 on: March 31, 2013, 02:49:55 PM »
I don't understand why the M+2 peak is so close to the M peak.

Nor do I.
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Offline Arkcon

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Re: Mass Spec with two different halogens?
« Reply #6 on: March 31, 2013, 03:41:00 PM »
This web widget http://www.sisweb.com/mstools/isotope.htm likewise gives (approximately) a 9:3:1 ratio for C11H12Cl2N2O5 (chloramphenocol).  The image 15.64 sure looks odd.  In the reference I have, it looks like a molecule with a single bromine.  Maybe the image is a typo, mislabeled from another problem in the text?
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Offline MOTOBALL

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Re: Mass Spec with two different halogens?
« Reply #7 on: March 31, 2013, 07:53:21 PM »
There seem to be some transcription errors; SIS gives 100/66.5/11,6 as expected

Offline orgopete

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Re: Mass Spec with two different halogens?
« Reply #8 on: April 01, 2013, 08:50:48 AM »
I don't understand why the M+2 peak is so close to the M peak.

Nor do I.

I would not either, however I am cynical about mass spectra. I searched for "chloramphenicol mass spectrum" and I scanned through several of the results. The NIST MS did not include the parent ions, presumably due to low abundance from fragmentation. The chemical ionization spectra did show the P+1 peaks, but the ratios were closer to the predicted values.

I have no reason to doubt the peak ratios of the posted problem, but I don't have any reason to think it is representative of the spectrum you may actually find in the lab under normal conditions (or similar to the published spectra).
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