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Topic: Formation of CuSO4  (Read 7436 times)

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Offline Boxxxed

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Formation of CuSO4
« on: March 18, 2013, 08:56:19 PM »
I have the log K of this reaction to be 2.31 but I don't know what the reaction is for the formation.

I have Cu2+ +H2SO4 ----> CuSO4 + 2H+

Is this correct?

If so, how would I calculate the ratio of Cu2+ to CuSO4.

All I have is the cu2+ concentration, CuSO4 concentration and the H+ concentration.

Offline Borek

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Re: Formation of CuSO4
« Reply #1 on: March 19, 2013, 04:05:37 PM »
Please elaborate - what is the real problem you are trying to solve, I find your question confusing.

H2SO4 doesn't exist in solutions, unless its a highly concentrated sulfuric acid.

What is CuSO4 - ion pair? Complex? Not that they are easy to distinguish, but it would be nice to know in what context we are discussing the problem.
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Offline Boxxxed

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Re: Formation of CuSO4
« Reply #2 on: March 19, 2013, 08:02:27 PM »
It is a CuSO4 complex. I have the SO4 concentration in a lake and I'm trying to figure out the ratio of free Cu to the complex in this lake. I also have the pH of the lake.

Offline Borek

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Re: Formation of CuSO4
« Reply #3 on: March 20, 2013, 04:53:30 AM »
If it is in the lake you don't have H2SO4 to start with, plus you most likely have plenty of other ions/molecules that will react with copper.
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