[Skribbez]

This is my first post so I guess Hi to all! Just wondering if somebody could check my work on this, please.

HCL_(aq) + Ba(OH)_2(aq) in a neutralisation reaction

H⁺ + Cl^- + Ba²⁺ + 2OH^- -> BaCl₂ + H₂O        : opposites attract

2HCL_(aq) + Ba(OH)_2(aq) -> BaCl₂ + 2H₂O   :balanced equation

And then, because Barium Chloride can be ionized in water and swipe an H⁺, the arrow becomes bidirectional. so the final equation should look something like this:

2HCL_(aq) + Ba(OH)_2(aq) <-> BaCl_2(aq) + 2H₂O_(liq)  ?

Does this look right or am I still missing something here?

[AWK]

H+ + Cl- + Ba2+ + 2OH- -> BaCl2 + H2O
If you write down reaction in ionic form it should be
H+ + Cl- + Ba2+ + 2OH- -> Ba2+ + 2Cl- + H2O