November 25, 2024, 10:20:39 AM
Forum Rules: Read This Before Posting


« previous next »
Pages: [1]   Go Down

Topic: E2 mechanism help  (Read 2207 times)

0 Members and 1 Guest are viewing this topic.

Offline craigms

  • New Member
  • **
  • Posts: 8
  • Mole Snacks: +0/-1
E2 mechanism help
« on: May 11, 2013, 01:27:56 AM »
Is anyone able to show me how this reaction would occur via E2?


KOBu(tertiary) in HOBu(tertiary)

I'm a bit confused doesn't the H need to be trans to the Br? In this case isn't the cyclic ring trans to the leaving group? or am I not getting it..
« Last Edit: May 11, 2013, 01:39:28 AM by craigms »
Logged

Offline discodermolide

  • Chemist
  • Sr. Member
  • *
  • Posts: 5038
  • Mole Snacks: +405/-70
  • Gender: Male
    • My research history
Re: E2 mechanism help
« Reply #1 on: May 11, 2013, 01:40:37 AM »
You have a trans H to the Br,
it's on the ring-CH2-CH2Br One of these is trans.
Logged
Development Chemists do it on Scale, Research Chemists just do it!
My Research History

Offline craigms

  • New Member
  • **
  • Posts: 8
  • Mole Snacks: +0/-1
Re: E2 mechanism help
« Reply #2 on: May 11, 2013, 02:01:40 AM »
Quote from: discodermolide on May 11, 2013, 01:40:37 AM
You have a trans H to the Br,
it's on the ring-CH2-CH2Br One of these is trans.

How so? Wouldn't it look like this, the R group being trans to the Br? Please explain I'm still confused.



R = cyclohexane
Logged

Offline hairygorillaz

  • Regular Member
  • ***
  • Posts: 34
  • Mole Snacks: +1/-0
Re: E2 mechanism help
« Reply #3 on: May 11, 2013, 02:19:13 AM »
There is rotation around the Cy-CH2-CH2Br bond.
Logged
Pages: [1]   Go Up
« previous next »
Sponsored Links