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Topic: Temperature and Free Energy with Equilibrium  (Read 2332 times)

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Offline 4evrastudent

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Temperature and Free Energy with Equilibrium
« on: May 20, 2013, 03:47:13 PM »
I'm asked to solve a problem given this chemical equation:

2SO(g)  ::equil:: 2SO2(g) + O2(g)

I'm given K = 1.32 at 900.15 K and asked to find the constant at 828.15 K.

I'm not really sure how to go about this, but I'm thinking that I would plug in the constant and temperature into the equation ΔG = -R*T*lnKeq

Then I'm thinking I would take the ΔG value and and plug it into the above equation with 828.15 K as the T value.

I've tried this and it doesn't seem to get me to the right answer. Could someone point me in the right direction? Do I have to go back and use ΔG = ΔH - TΔS

Thanks!

EDIT: My notation was messed up.
« Last Edit: May 20, 2013, 05:58:18 PM by 4evrastudent »

Offline Corribus

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Re: Temperature and Free Energy with Equilibrium
« Reply #1 on: May 20, 2013, 05:18:45 PM »
Look up the Van't Hoff equation.

http://en.wikipedia.org/wiki/Van%27T_Hoff_Equation

(Using your approach won't work because ΔG is not invariant to temperature.)

EDIT: By the way, your equation doesn't seem to be balanced.
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Offline 4evrastudent

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Re: Temperature and Free Energy with Equilibrium
« Reply #2 on: May 20, 2013, 06:05:29 PM »
Look up the Van't Hoff equation.

http://en.wikipedia.org/wiki/Van%27T_Hoff_Equation

(Using your approach won't work because ΔG is not invariant to temperature.)

EDIT: By the way, your equation doesn't seem to be balanced.

Thank you, that chemical equation is not correct. The correct one is:
2SO3(g)  ::equil:: 2SO2(g) + O2(g)

Just to clarify, the equation I want is this one: ΔG = -R * T * lnKeq

Offline Corribus

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Re: Temperature and Free Energy with Equilibrium
« Reply #3 on: May 20, 2013, 11:05:13 PM »
Well, you really need ΔH.  This is not given?  Are you allowed to look up this value?
Otherwise I'm not seeing at first glance how to solve the problem. 
What men are poets who can speak of Jupiter if he were like a man, but if he is an immense spinning sphere of methane and ammonia must be silent?  - Richard P. Feynman

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