I don't about about the applicability of this universally to all substances. But for one instance (Cu, i believe), I remember seeing two different chemical reactions (equations) being written for the concentrated and diltue acids.
http://www.angelo.edu/faculty/kboudrea/demos/copper_HNO3/Cu_HNO3.htmAs you would expect and can see in the link above, amount of HNO
3 used per Cu is lesser in the dilute case as compared to the concentrated one. Yet, the amount of Cu(NO
3)
2 produced per Cu is the same. Basically, the product formed in the dilute acid is in the same ratio with the metal, even though you're using lesser acid-per-metal. Which means, it's more 'potent'. Atleast this was my interpretation. The by-products vary.