[snovid]

how many the energy of oxygen combustion that convert to electric in kWh/scm O2
if graphite assumption is 10 ton
C+1/2O2= CO.. delta H at 1620 degre = 116,05 kJ/mol
so what if the unit is kWh/scm O2??

[Hunter2]

kWh = Kilowatthour, scm = standard cubicmeter = 1 m³

http://www.npd.no/Global/Norsk/6%20-%20Om%20OD/Oljeordliste/Omrekningsfaktorar_engelsk.pdf

http://www.gail.nic.in/final_site/energyconversionmatrix.html

[snovid]

scm is standart cubic meter
in volume ideal gas is 22,4

[Hunter2]

22,4 l means 1 mol at 32° F or 0° C

[snovid]

at 25° C

[Hunter2]

No:

http://en.wikipedia.org/wiki/Molar_volume

at 25 °C its 24,8 l

[billnotgatez]

confused

from WIKI

The molar volume of an ideal gas at 100 kPa (1 bar) is

    22.710 980(38) dm3/mol at 0 °C
    24.789 598(42) dm3/mol at 25 °C

The molar volume of an ideal gas at 1 atmosphere of pressure is

    22.414 L/mol at 0 °C
    24.465 L/mol at 25 °C

[snovid]

No:

http://en.wikipedia.org/wiki/Molar_volume

at 25 °C its 24,8 l

thx for the correction, but same as bfore ... it's still confusing too

[Hunter2]

First calculate how much oxygen (mol) is need to combust 10 tons carbon.

This amount you have to convert to the volume.

 delta H is given.  Temperature is given.

kWh/m³ hint 1 Ws = J

volume expressed by pV = n RT

[snovid]

O2= 1333.3 kg x 24,8= 33065.8 ??
so what should i do with the temperature and delta H
 please give me the formula of it.
 it's must prove that delta H =2,73 kWh/scmO2

[Hunter2]

Try to convert the unit kJ/mol to kWh/m³. Hints are given. the 22.4 l doesn't work, because temperature is 1620 degree.

[magician4]

confused

from WIKI

The molar volume of an ideal gas at 100 kPa (1 bar) is

    22.710 980(38) dm3/mol at 0 °C
    24.789 598(42) dm3/mol at 25 °C

The molar volume of an ideal gas at 1 atmosphere of pressure is

    22.414 L/mol at 0 °C
    24.465 L/mol at 25 °C

1 atm [itex] \neq [/itex] 1 bar
( 1013,25 mbar = 1013,25 hPa = 1 atm )

hence the slightly different numbers

regards

Ingo