IMHO , the only "clean" definition of the concentration of a salt would be the one related to the (theoretical) c
0(salt) , i.e. what you would gain if the salt was in the solution stand - alone, and none of the ions would react any further.
... as with everything else you'd run into problems like the ones you're facing.
Now, for practical purposes, for example when you're dealing with mixed solutions, you'd have to come up with problem related "definitions" of your own.
example:
when dealing with the problem you posed, I would indicate even equal ions by the source they came from, like " Cl
-(AgCl)" and "Cl
-(KCl)" (as I would need those sources anyway).
For your problem, my solution then would look something like this:
general solubility product for AgCl : K
sp = [Ag
+] * [Cl
-]
after that:
calculation of the solubility product at 50°C from "ΔG (T) = -RT lnK
sp(T) " and "ΔG(T) = ΔH - TΔS"
with this:
K
sp(50°C) = [Ag
+]
50 * [Cl
-]
50 = [Ag
+]
250 [Ag
+]
50 = [itex]\sqrt {K_{sp}(50°C)}[/itex]
moving on:
K
sp(25°C) = [Ag
+]
50 * ( [Cl
-]
50 + [Cl
-]
(KCl) ) = [Ag
+]
50 * ([Ag
+]
50 + [Cl
-]
(KCl)) = [itex]\sqrt {K_{sp}(50°C)}[/itex] * ([itex]\sqrt {K_{sp}(50°C)}[/itex] + [Cl
-]
(KCl))
hence:
[tex] [Cl^-]_{(KCl)} = \frac {K_{sp}(25 °C ) }{\sqrt {K_{sp}(50°C)}} \ - \ \sqrt {K_{sp}(50°C)} [/tex]
... and this chloride concentration would be directly related to the c
0 of the original KCl solution you were asked about
regards
Ingo