[Needaask]

In my exam paper tod) we had a weird question where they asked us to find the Keq of a reaction with the Delta G of a reaction at 1173K. So the first thing that went into my mind was to use Delta G°=-RTlnkeq. However, the question specifically said to use the Delta G at 1173K provided. So, I used! H formula Delta G=Delta G°+RTlnQ and solved for Q. But instead of Q I wrote Keq instead.

Did I do something wrong? I didn't want to ask the teacher about this because he hasn't even taught the class what's Q but only Keq. So I think he meant to set the question as what is the Q at 1173K since he specifically wanted the Delta G term to be present in the workings. Do you think I'm right about this?

on aother note, the Delta G found was found by using the formula Delta G=Delta H-Tdelta S. So that would be the actual change in Gibbs free energy. But then why would the Delta G go to 0 after a while? Because wouldn't that mean for all reactions eventually no more free energy would be absorbed or given out? That seems weird to me as in most question we simply used the formula Delta G=Delta H-TdeltaS to get a non zero value. So How would this formula remain relevant when any Delta G value found using that formula would go back to zero?

Thanks for the help