I am studying for a Biochemistry I class and I have hit a brick wall and I would greatly appreciate some help.
Problem:
A peptide is composed of Tyr, Tyr, Arg, Asp, Thr, His, Met, and Lys.
- Treatment with cyanogen bromide yielded a free Met and a heptapeptide.
- Treatment with Trypsin yielded a tetrapeptide with a net positive charge at a pH of 5, a free Thr, and a tripeptide.
- Chymotrypsin treatment yielded a tripeptide , a dipeptide, and tripeptide with a net negative charge at pH of 12.
What is the sequence?
What I know:
- CNBr cleaves Met at the C-terminus
- Trypsin cleaves Arg and Lys at the C-terminus
- Chymotrypsin cleaves Tyr, Phe, Trp at the C-terminus
- The pKa of His at its imidazole is ~6
- The pKa of Lys at its amine is ~10
- The pKA of Arg at its amine is ~12
- The pKA of Asp at its side chain carboxylic acid is ~3
My attempt at a solution:
I have determined that Met is the first in the sequence, because it is cleaved at the C-term by CNBr. Ser must be the last in the sequence because Trypsin must cleave at the C-term of Lys and Arg. The Tetrapeptide must contain histidine since it has a net positive charge at pKa 5. I don't know where to go from here because there are several possibilities for cleavage. I don't know what useful information net negative charge at pH 12 of one tripeptide as a result of Chymotrypsin treatment is suppose to give me.