[Promilla]

Hello everyone. I have a few questions - I do not want any answers whatsoever, just perhaps clues or tips whether or not I am going in the right direction.

So basically, I had to measue pH of few solutions. I have some problems with writting reactions to explain my observation. 

So:

1)SnI₄ - so first we have dissociation. Is this reaction correct: SnI₄ +6H₂O [Sn(H₂O)₆]⁴⁺+4I^- ?

Then, immidiatelly I saw white precipitate which suggest this reaction occurs: [Sn(H₂O)₆]⁴⁺ + 4H₂O  [Sn(H₂O)2(OH)₄]_(s) + 4H₃O⁺ ? Is it correctly written?
Of course it is not a single reaction but four, but is it ok to write it like that?

2) Then we have (DMSO)₂SnI₄ . \
I have no idea how the dissociation would look like. The precipitate in this case fell out from the solution after longer period of time, so I assume it cannot loose DMSO ligand so quickly. Could you please advise me how the reactions may look like. Does the fact, that DMSO has electron-donating ligand play a significant role here?

Two more questions perhaps a bit unrelated:
1) Does Magnesium exist in a solution as [Mg(H₂O₆]²⁺ or something different?

2) What technique can be used to differentiate the two geometrical isomers of  (DMSO)₂SnI₄? I know we will have cis and trans, and their hysical or chemical properties would differ a bit, but is there a particular way to differentiate them.

I would truly appreciate your answers.

Thank you in advance.

Promilla

[antimatter101]

Your last statement could be EASILY answered if you did the tinyest bit of research.

Since there is a total of six ligands (DMSO is monodentate), they the complex would adopt an octahedral formation according to VSEPR.

Octahedral complex stereochemistry is defined by four terms: cis-trans, and fac-mer.

Search up facial-meridonial on google. These are stereochemistry definitions.