Which one is more soluble in CF4? O2 or N2? Using geometry and intermolecular forces rules...
My guess...
CF4 is a tetrahedrical, nonpolar compound, so he has only "london dispersion forces"
N2 is nonpolar, only with london and so O2.
So the thing to compare is Molecular mass, Mr(N2)=28 Mr(O2)=32 and Mr(CF4)=88.... I suppose O2 will be more alike (closer to CF4 mass) furthermore more soluble.. a tiny bit; what do you think?
Remember, this thing empirically...