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Determing pH of aqueous solution
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Topic: Determing pH of aqueous solution (Read 6328 times)
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rcoleman
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Determing pH of aqueous solution
«
on:
March 05, 2006, 02:32:40 PM »
I have 2 questions:
1) Which of the following aqueous solutions gives a pH greater than 7?
The answer choices are 10e-8M HCOOH, 10e-8M NH4Cl, 10e-8M CH3COOH, 10e-8M HCL. I was thinking that none of these solutions gives a pH greater than 7 because I don't think any of them are bases.
2) *This is a mathematical problem which I'm pretty sure I did right but I need some clarification.*
Calculate the pH of the solute in an aqueous solution of 0.135M C5H5N (aq) (pyridine) if the Kb is 1.8e-9.
Here's my work:
1.8e-9 = x^2/0.135-x
2.43e-10 - 1.8e-9x - x^2 = 0
Quadratic Formula:
[-(-1.8e-9) +\- sqrt((-1.8e-9)^2-4(1)(2.43e-10))]/2(-1) =
1.8e-9 +\- 5.2650e-5\-2 = 2.6324e-5
pOH = -log(2.6324e-5) = 4.5796
pH = Kw - pOH = 14 - 4.5796 = 9.42035
I thought that was right but when I entered in the answer it was wrong. I believe I did all of the steps right. Can anyone help me?
Thanks.
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Albert
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Re:Determing pH of aqueous solution
«
Reply #1 on:
March 05, 2006, 02:46:35 PM »
The former is correct.
For what concerns the latter, C
b
/K
b
>100.
Hence: [OH-] = (C
b
*K
b
)
1/2
I got pH = 9.19 using this method.
I didn't check how you solved the quadratic equation, but, if you want, I can post it.
«
Last Edit: March 05, 2006, 02:55:40 PM by Albert
»
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Determing pH of aqueous solution