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Topic: Deviation from Raoult's law problem  (Read 1284 times)

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Offline Needaask

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Deviation from Raoult's law problem
« on: November 10, 2013, 11:10:53 AM »
When we have a positive deviation that means the bonds between A-A and B-B are stronger than A-B. and so, A-B prefers to leave the solution as there is additional repulsion between them.

However, in an example given of CS2 and H2O where positive deviation occurs, the CS2-H2O bond is stronger than the CS2-CS2 bond because the dipole-induced dipole bond is still stronger than the London dispersion forces in CS2. While the dipole-dipole bond in water is still stronger, now unlike the A and B scenario given A-A (representing water) is stronger than A-B but B-B (representing CS2 london dispersion forces) is weaker. So how does this example show the positive deviation?

Thanks in advance :)

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