[Anonymous2468]

I need some help with these:
The solubility of solid ZnCO3 is enhanced in acid, due to the reaction of carbonate with acid.
(Note: in the balanced equation for this process, you only need one mole of acid to react with the one mole of carbonate in the solid.)

b)Using the equilibrium constant, 2.13,  what is the molar solubility of ZnCO3 at pH = 4?

I tried doing 2.13=x^2/(-log(14-4)) but that didnt get me the right answer so im stuck....

Im having problems figuring out the overall rxn...I would think the rxn would be:
2ZnCO3 +2H3O ------->  2Zn2+ 3H2O + 2CO2

except my oxygens dont add up  so I dont know how fix my equation...

[Borek]

Question is poorly worded. My bet is that they refer to the reaction

ZnCO₃ + H⁺ Zn²⁺ + HCO₃^-

[Anonymous2468]

Yeah thanks for that! Although, I figured out that I was just putting it in my calculator wrong lol