[emissivity]

   Hi! I have a question for the term symbol. This is the problem.
"What terms arise from a p¹d¹ configuration?"

I'll show you the process that I had done. 

   At first, there are two electrons in two orbitals(l₁=1 for p, l₂=2 for d)
   Secondly, each electrons have +1/2 spin respectively.
   Next, I tried to find "L", "S"
      1. For L, "2+1=3", "2-1=1", "2+1-1=2". As a result, L=3,2,1 which mean F,D,P
      2. For S, "1/2+1/2=1", "1/2-1/2=0". Thus, S=3,1
   Finally, there can be ³F, ¹F,³D, ¹D,³P, ¹P

But! the solution says ³F, ¹F are possible. What problems did I have while I was doing this?
Please help me!

[Corribus]

I'm a little confused by your post.  You say you got the answer: "Finally, there can be 3F, 1F,3D, 1D,3P, 1P".  Then you write: "But! the solution says 3F, 1F are possible.".  You seem to have gotten 3F, 1F in your reported answer.  So what's the problem?

[emissivity]

I'm a little confused by your post.  You say you got the answer: "Finally, there can be 3F, 1F,3D, 1D,3P, 1P".  Then you write: "But! the solution says 3F, 1F are possible.".  You seem to have gotten 3F, 1F in your reported answer.  So what's the problem?

Well, I've been just wondering why "3D, 1D,3P, 1P" was not in the solution book.
Are not they possible?

[Corribus]

What was the precise wording of the question?

[emissivity]

What was the precise wording of the question?

It is "What terms arise from a p¹d¹ configuration?" exactly.

This problem is on the book, Inorganic chemistry 5th ed, Shriver, Atkins.

And I refered to the solution textbook but there were only two answers.

[Corribus]

I believe your answer is the correct one.