The boiling point of benzene (Mm = 78.0 g/mol; kb = 2.53ºC/m; ρ = 0.877 g/mL) is 80.1ºC. What mass of vanillin (mm = 152.1 g/mol; non-electrolyte) is required as a solute to raise the boiling point of 44.6 mL of benzene to 81.2ºC?
Solvent (benzene)
Tºb = 80.1ºC
kb = 2.53ºC/m
ΔTb = 81.2ºC
Mm = 78.9 g/mol
ρ = 0.877 g/mL
V = 44.6 mL
Solute (vanillin)
Mm = 152.1 g/mol
i = 1 (non-electrolyte)
ΔTb = kbmc
ΔTb = kb(1 * m)
ΔTb = kb(1 * mol solute/mass kg solvent)
81.2 = (2.53)(mol solute/___ mass kg solvent)
Solve for mass kg solvent (benzene)
44.6 mL x 0.877 g/mL = 39.1142 g = 0.039 kg solvent, right?
Am I on the right track??