[Altered State]

Does this work?

Acetone ---(D2O/NaOH)---> Hexadeuterated acetone

If not, any other way to obtain deuterated acetone using only D2O, LiAlD4 or D2 as deuterium source?

[Archer]

What you have suggested would work but you would get self conensation products too.

I am not familiar with the actual process used but a weaker base may be employed (Na₂CO₃ for example.

[Enthalpy]

You should give a thought at:
- What proportion of ¹H you accept in the desired product
- What proportion of ¹H this implies in the D₂O at the end of the exchange
- Consequently, what amount of D₂O reactant you need, to throw it away when it's 1% or 0.1% used.

The result uses to be devastating. Typically, if you accept 1% ¹H in your product, you must discard the D₂O before it contains 1% ¹H, hence consume 100 times too much D₂O.

You might get inspiration from that other thread:
http://www.chemicalforums.com/index.php?topic=70989
try to synthesize acetone and have from the beginning pure deuterium everywhere?
Have something like CBr₃-CO-CBr₃ as an intermediate step? Recycle DBr.
Use a kind of COX₂ (yuk cough cough) and CD₄ as reactants?
Well, you chemists can tell that better.

To the very least, if you stick to exchanging H and D between acetone and water, you should do it with successive pots of increasing concentration, as inspired by this:
http://www.chemicalforums.com/index.php?topic=68477.msg253833#msg253833
that will reduce the unreasonable consumption of D₂O.