[rainrider]

Ok, I know I'm missing something, but I can't figure out what...

I'm given the following:

How many grams of CO₂ is released when 1kg of C₈H₁₈ combusts.

I set up and balance the formula:

2C₈H₁₈ + O₂ --> 16CO₂ + 18H₂O

Now, as I understand it (which is apparently wrong), you use the ratio of moles of octane (C₈H₁₈) to carbon dioxide to calculate the actual number of grams you would get out, as such:

1000g octane x (1 mol octane)/(384.08g) x (8 mol CO₂/1 mol octane) x (44.01g CO₂/1 mol CO₂) = 916.7g of CO₂.

The answer the book gives is 3.1kg of CO₂.

I'm not sure where I'm going wrong...does someone else know?

Thanks!

[AWK]

C8H18 + 12.5O2 --> 8CO2 + 9H2O
Calculate correctly mole of octane!

[tennis freak]

C8H18 + 12.5O2 --> 8CO2 + 9H2O
Calculate correctly mole of octane!

once you get the correct balanced formula you use the same exact equation you did like this

1000 g C8H18 * (1mole/114g) * (8 mole CO2/1mole C8H18) * (44gCO2/1moleCO2)= 3087.72 g CO2 which translates to about 3.1 kg CO2 depending on how you rounded