[my59vw]

I need help converting from percent chloride to percent zinc chloride. Is it as easy as

10% Cl x (136.315 ZnCl2 /35.453 Cl) = 38.45% ZnCl

[Borek]

Chances are you are right. But without context it is hard to be sure.

[my59vw]

Well the problem is to calculate the zinc chloride and ammonium chloride concentration if the solution is 10% chloride. So I calculated the zinc chloride concentration as above as well as doing the same for ammonium chloride.

[Borek]

Oops, there are no chances you are right, I am an idiot.

How many moles of ZnCl₂ per mole of chlorine (hint: no formula for purpose)?

If the solution contains 10% of chlorides and is a mixture of zinc chloride and ammonium chloride, there is not enough data to solve.

[my59vw]

So it should be


10% Cl x (136.315 ZnCl2 /(2 x 35.453 Cl)) = 19.225% ZnCl2

For the ZnCl2 portion?

[my59vw]

Or So it should be


10% Cl x (136.315 ZnCl2 /(2 x 70.906 Cl2)) = 9.6125% ZnCl2

For the ZnCl2 portion?

[Borek]

Yes, one of those.

2×70.906=141.8, so it would mean 136.3 g of ZnCl₂ contains 141.8 g of Cl₂.