(mL H2O / 1.188 g H2O)
This is not 1.188 g of H
2O, but 1.188 g of solution.
As far as I can tell this is not just a simple application of conversion factors. Assume you have 1 L of the solution, find number of moles of maltose and mass of solvent, then use these to calculate molality.
2.11 m is a correct answer btw.