[Ocsw56]

Oxidation lab involving Cyclohexanol (den 0.96, MW 100.2) to cyclohexanone (den0.97, MW 98.14) by hypochlorite oxidation (MW 74.392 g/mol,5.25% w/v)

I need to convert the amt of sodium hypochlorite used into mmol.

2.3ml of a 5.25% solution of sodium hypochlorite was used.

My thoughts were: 5.25*2.3ml / 74.392 =0.162316 mol*1000mmol/1mol=162 ?

Asking for direction on how to calculate this one please.

Thanks

[Benzene]

Is 5.25% by weight? by volume?

[Ocsw56]

it says 2.5 ml of a 5.25% solution of sodium hypochlorite (I am thinking by weight ?)

Thank you

[discodermolide]

If its 5.25%w/V then it has 5,25 g /100 mL.
I don't see that factor in your calculations if it's mL then
you should surely have (5.25g*2.3mL)/100mL gives a figure in G which you now must convert to moles.