Hi,
Sabrina heats up one steel rod of 50 g. When the rod is 85 °C, she puts it in a themor containing 225 g of ethnaol, at a temperature of 20 °C. The temperature of the ethanol goes to 22,6 °C. If we consider that there isnt any loss of energy in the environment, what is the specific heat capacity of steel?
Q=m.c.delta t
= 225 g . 2,46 J/g .°C. (22,6-20) °C
= 1439,1 J
C= Q/(m. delta t)
= -1439,1 J/(50 g * (final temp-85)
My only problem was how can I know the final temperature
Finally, when I saw what the solution was, I was kind've disturbed. It says that the finaly temperature of the steel is 22,6... How do they know that ? Why couldn't it be 30, ,40 ,etc. °C ?
Can somebody explain me ? THank you!
*By the way, your verification process for registration was hard -__-. (It's barely readable)