I'm working with my grad student on a long synthesis problem...helping him make the synthesis of our final product faster/easier lab work and better yields. The reaction I'm looking at at the moment is the protection of L-valine methyl ester HCl with boc anhydride so we can do a grignard reaction on the methyl ester. I've asked several professors and found contradicting papers on whether this reaction needs to be under anhydrous conditions or not.
Our present synthesis is as follows:
Solid sodium hydrogencarbonate (14.4 g, 170 mmol) was
added in one portion to a stirred solution of l-valine methyl ester hydro-
chloride (9.5 g, 56.7 mmol) in dry tetrahydrofuran/methanol (4:1)
(150 mL) at 0 8C, immediately followed by addition of solid Boc2O
(18.5 g, 84.9 mmol). The reaction was allowed to warm to room tempera-
ture, stirred for 20 h and then quenched with water (100 mL). The organ-
ic product was extracted with diethyl ether (2 300 mL), washed with sa-
turated sodium hydrogencarbonate (2 100 mL), brine (2 100 mL),
dried over magnesium sulphate and concentrated in vacuo. Purification
of the crude product by flash column chromatography (silica gel; hexane/
ethyl acetate 9:1 ! 6:1) afforded 8 as a colourless oil
this is a proposed alternative to the reaction above:
http://dx.doi.org/10.1016/j.tetlet.2007.09.126There are several other papers I found using water as a solvent, or not caring that the materials in the reaction were not water free. So, what I'm hoping is that someone can help me with is explain why or why not the boc2o hydrolysis is a competing reaction with the protection step and if so how much it will effect the yields, and what best step to go about the synthesis - base catalyzed or acid catalyzed
(mod edit to shorter link, sjb)