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Topic: calculate a value for Kc  (Read 9648 times)

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biomed77

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calculate a value for Kc
« on: March 15, 2006, 03:21:32 PM »
cyanide ions are poisonous because they complex with Fe2+ and Fe3+ ions in haemoglobin and in enzymes. the equilibrium is: Fe3+  +  6CN <--->[Fe(CN)6]-3
write an expression for the equilibrium constant Kc and calculate a value for Kc if the concentration were found to be
Fe3+= 1*10^-6   CN- = 3*10^-6    [Fe(CN)6]3- =  1*10mol dm^-3

Aswer: T he equation  for Kc is:  Kc=[Fe(CN)6 3-] / [Fe3+][CN-]^6

so Kc= [1*10^-8] / [1*10^-6][3*10^-6]^6
= 1.37*10^31
can someone please tell me if it is right?? thanks a lot

Offline Albert

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Re:calculate a value for Kc
« Reply #1 on: March 15, 2006, 03:41:32 PM »
Yes, it is. I think I already answered this very question.
« Last Edit: March 15, 2006, 03:41:49 PM by Albert »

biomed77

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Re:calculate a value for Kc
« Reply #2 on: March 15, 2006, 03:44:01 PM »
thank you, it was a previous question that you ve answered...thanks again

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