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Topic: Kinetics question  (Read 1690 times)

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Offline sn1sn2e1e2

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Kinetics question
« on: March 19, 2014, 09:40:16 PM »
2 NO (g) + Cl2 (g)  :rarrow: 2 NOCl

Which is/are required for a successful reaction between NO and Cl2 molecs?

I. Proper orientation
II. NO/Cl2 Ratio of 2 to 1
III. Sufficient collision energy

I chose I, II, and III since ...
I(if Nitrogen of NO hits the Cl of Cl2, no reaction will occur since O must hit Cl)
II (trimolecular)
III (to surpass Ea)

However, the correct answer excludes II and only chooses I and III ONLY.

I thought II is needed for a successful reaction (mole to mole ratio)

Any help?  :D

Offline sjb

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Re: Kinetics question
« Reply #1 on: March 20, 2014, 03:20:35 AM »
2 NO (g) + Cl2 (g)  :rarrow: 2 NOCl

Which is/are required for a successful reaction between NO and Cl2 molecs?

I. Proper orientation
II. NO/Cl2 Ratio of 2 to 1
III. Sufficient collision energy

I chose I, II, and III since ...
I(if Nitrogen of NO hits the Cl of Cl2, no reaction will occur since O must hit Cl)
II (trimolecular)
III (to surpass Ea)

However, the correct answer excludes II and only chooses I and III ONLY.

I thought II is needed for a successful reaction (mole to mole ratio)

Any help?  :D

Maybe for a successful complete reaction (with no waste etc); but you could envisage perhaps mixing 3 mols of NO and 1 of Cl2 to yield 2 mol of NOCl and having 1 of NO left over. In fact, given the scales involved it would be very difficult in practice to ensure that you have the exact proportion of reactants involved in any reaction.

Offline Corribus

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Re: Kinetics question
« Reply #2 on: March 20, 2014, 09:48:14 AM »
In fact, we usually purposefully do NOT use the correction mole ratios, because to do so would result in a very slow conversion to products. As reactants get consumed, the probability of a successful collision decreases.  For this reason, it is common to use at least one reagent in excess to help drive the consumption of the limiting reagent to completion.
What men are poets who can speak of Jupiter if he were like a man, but if he is an immense spinning sphere of methane and ammonia must be silent?  - Richard P. Feynman

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