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Topic: Allylic Carbocation  (Read 3962 times)

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Offline d.beser

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Allylic Carbocation
« on: March 21, 2014, 10:22:32 AM »
Loss of Chloride ion from 1-(chloromethyl)-4-methylcyclopentene produces an allylic carbocation that has two resonance structures.

What is at least one of them

I am not to sure where to start with this question...

Offline discodermolide

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Re: Allylic Carbocation
« Reply #1 on: March 21, 2014, 10:23:40 AM »
start by drawing all the structures
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Offline d.beser

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Re: Allylic Carbocation
« Reply #2 on: March 21, 2014, 10:26:40 AM »
I have! What is given to me is a cyclopentane with a ethyl group and a methyl group and now I am to drawn the resonance structure of it. Not to sure how they want me to demonstrate the resonance structure.

Offline Babcock_Hall

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Re: Allylic Carbocation
« Reply #3 on: March 21, 2014, 10:50:12 AM »
Once you have the structure of the starting material, take the chlorine atom away with both electrons.  If you have gotten that far already, good.  What can move when you draw multiple resonance structures, and what must stay in place?  Feel free to show us your drawing.

Offline orgopete

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Re: Allylic Carbocation
« Reply #4 on: March 21, 2014, 10:57:04 AM »
I have! What is given to me is a cyclopentane with a ethyl group and a methyl group and now I am to drawn the resonance structure of it. Not to sure how they want me to demonstrate the resonance structure.

You need to be careful with the name. In the first post, it said cyclopentene, which has a double bond, not cyclopentane. Also, no ethyl, but this may have been a typo.
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