Hi guys,
I have this titration question which I can't solve.
25 mL of a 0.095M of acetic acid was diluted to 100mL with deionized water and titrated with 0.101M of NaOH.
The equation for the reaction occurring is CH3COOH (aq) + NaOH (aq) -> CH3COONa (aq) + H2O (aq)
a) Calculate the number of moles of sodium acetate formed at equivalence point. (I used around 23.1 mL of NaOH)
b) Calculate the concentration of sodium acetate at equivalence point.
c) Then using the equation pH = 1/2pKw + 1/2pKa + 1/2logc, calculate the pH at the equivalence point. (my pH comes out to about 1.86 here which is totally off the expected value)