[cakilu300]

NOTE: the ice must be at 0°C so, if taken out of a freezer, it must be left at room temperature and allowed to partially melt. "Dry" each ice chunk with a towel before adding to the calorimeter so that you are adding only solid, no liquid. Your collected data should look similar to the time-temperature curve above. 
CALCULATIONS:
Specific Heat of water at room temperature is... 4.180 j/g °C .
The heat gained or lost by water is.. joules = (4.180 j/g °C) (temperature change)(mass) 
Experimental Data 
Mass of empty calorimeter and stirrer..   12.43 g
Mass of calorimeter, stirrer and hot water..   51.45 g
Mass of calorimeter, stirrer and water at the end...   68.47 g
Calorimeter Constant.....   0.794 j/oC
Temperature of Hot Water.....   71.54 oC
Final temperature of water in calorimeter....   25.63 oC
CALCULATE: (to the correct number of sig figs; use correct units; mass in g (grams), energy in j (joules)). a)   Mass of hot water used....  __________39.02______ 
b)  Mass of ice added...  _______17.02________ 
c)   Temperature decrease of hot water....  ________45.91_______ °C
d)   Temperature increase of the melted ice...  _____25.63__________ °C
e)   Heat lost by the hot water ...  _______7488________ 
f)   Heat lost by the calorimeter .  _______36.45________ 
g)   Heat gained by the melted ice water .  _____1823.4__________ 
h)   Heat of Fusion per g of ICE...  _______________ 
h)   Entropy change melting ice @ 273.15 K  _______________ j/mol K

I need help with the last
2 just help me figure out how to do it 

[Borek]

How much heat was used for melting the ice?