Hi, I'd just like to check my method for working this out isn't wrong, the last answer seems too large a value to me! Sorry if it's hard to follow
Air is composed of 80% nitrogen at sea level where the pressure is 1 bar.
A human with a body weight of 80 kg has an average blood volume of 5.6 L.
Henry’s law constant for the solubility of nitrogen in water: 9.04 × 104 bar at 298 K.
Assume that blood has identical properties to water (Henry’s law constant, density and relative molecular mass).
At sea level, calculate the number of moles of nitrogen absorbed in the blood of a human with a body weight of 80 kg.
5.6L of blood RMM = 20
5.6L = 5.6 dm3
xsolute = Psolute/kHsolute
1/9.04x104 = 1.106x10-5
xsolute = 1.106x10-5
nsolute = 1.106x10-5 x nsolvent
mass of water = volume x density = 5600cm3 x 1g cm-3 = 5600g
nsolvent = mass/RMM = 5600/18 = 311.1 moles
nsolute = 1.106x10-5 x 311.1 = 3.44x10-3 moles
At a pressure of 5 bar, calculate the number of moles of nitrogen absorbed in the blood of a human with a body weight of 80 kg.
P/kH = xsolute
5/9.04x104 = 5.531x10-5
nsolute = xsolute x nsolvent = 5.531x10-5 x 311.1 = 0.017 moles
Outline briefly how this equation is obtained from first principles.
I have no idea on this one, does it mean how it's derived?
Assume that a diver accustomed to breathing compressed air at a pressure of 5 bar is suddenly brought to sea level. What volume of N2 gas is released as bubbles in the diver’s bloodstream?
Gas constant: 8.314 × 10–2 L bar mol–1 K–1
At 5 bar diver has 0.017 moles N2 in blood
At 1 bar (sea level) 3.44 x10-3 moles
0.017 - 3.44 x10-3 = 0.01356 moles of N2
pV = nRT
V = nRT/P
V = (0.01356 x 8.314x10-2 x 298)/1
V = 0.33 L - this just seems like too much to me if it's only 0.01356 moles nitrogen?