Topic: Help with a reaction...? (Read 3189 times)

JMaria · « **on:** July 28, 2014, 10:05:14 PM »

So I have a reaction with 2-methyl-2-octene (lq) and HCl (lq) with heat and CH2Cl2.

I think the HCl adds in Markovnikov fashion but I've only seen the CH2Cl2 associated with halogenation and the heat with radical reactions so I'm not sure what it's there for.

discodermolide · « **Reply #1 on:** July 28, 2014, 10:53:25 PM »

As a solvent?

JMaria · « **Reply #2 on:** July 28, 2014, 11:22:36 PM »

Well it has the 2-methyl-2-octene and then + HCl and then an arrow beside it with a delta on top and a CH2Cl2 on the bottom.

discodermolide · « **Reply #3 on:** July 29, 2014, 02:04:26 AM »

Then it is a solvent

JMaria · « **Reply #4 on:** July 29, 2014, 02:42:32 AM »

So is the product 2-chloro-2-methyloctane? And the heat is required for the reaction to occur and the methylene chloride is the solvent which can be in excess?

phth · « **Reply #5 on:** July 29, 2014, 03:06:42 AM »

Yes, that is the product. Heat speeds the reaction up exponentially (k_forward), and it increases the yield (k_forward/k_backwards. The solvent is in excess.

Topic: Help with a reaction...? (Read 3189 times)

JMaria

Help with a reaction...?

discodermolide

Re: Help with a reaction...?

JMaria

Re: Help with a reaction...?

discodermolide

Re: Help with a reaction...?

JMaria

Re: Help with a reaction...?

phth

Re: Help with a reaction...?

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