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Topic: Percents,Molarity, and Normality  (Read 4810 times)

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Pochiyama

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Percents,Molarity, and Normality
« on: March 26, 2006, 07:39:47 PM »
Hello, I have a problem involving percents,molarity, and normality.
This is the problem:
Molarity of acetic acid=normality/mol of acetic acid*percent acetic acid=
Molarity of acetic acid=normality/mol of acetic acid*93.75%=
This is the reaction for acetic acid:CH3COOH + NaOH ---> NaOOCCH3 + H2O
I don't have the normality for acetic acid and I don't know how to get it all I know
is that acetic acid 1 equivalent. Help will be greatly appreciated.
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Offline Borek

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Re:Percents,Molarity, and Normality
« Reply #1 on: March 27, 2006, 02:49:54 AM »
Please elaborate, you haven't posted any question here, just some unrelated information.
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Paradoxtom

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Re:Percents,Molarity, and Normality
« Reply #2 on: March 27, 2006, 11:57:28 AM »
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