Hi, I was doing a textbook problem regarding the van der Waals equation and my textbook is giving me an answer I don't think is right. Can anyone verify?
Q. Suppose 10.0 mol ethane gas is confined to 4.860 L at 300 K. Predict the pressure exerted by ethane from (a) the perfect gas...given: a = 5.507 L^2 atm mol^-2, b = 0.0651 L mol^-1.
So when they say "confined to 4.860 L," I am supposed to take that as V_measured is 4.860 L and therefore
[tex]V_{ideal}=V_{measured}-nb=4.860 L-(10.0 mol)(0.0651\frac{L}{mol})=4.209L[/tex]?
Therefore...
[tex]p_{ideal}=\frac{nRT}{V_{ideal}}=\frac{(10.0 mol)(0.08206 \frac{L*atm}{mol*K})(300 K)}{4.209 L} = 58.4 atm[/tex]
And the answer is 58.4 atm, correct?
In the answer key to the book they used 4.860 L to calculate the pressure of the ideal gas and they get 50.7 atm. Is this not incorrect to do since 4.860 L is not the volume of the ideal gas?
Thanks