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Topic: finding ph of this problem  (Read 1810 times)

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Offline duma

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finding ph of this problem
« on: November 02, 2014, 08:21:21 PM »
50.11 mL 0.1101 M NaOH mixed with 75.32 mL of 0.1011 M acetic acid (pKa 4.757

 find pH

so far  I got:
 

AA = (75.32ml)(0.1011)-(50.11ml)(0.1101) = 0.016724 mmol AA

I know I need to use the Henderson Hasselbach equation, but I have no idea where to go form here.

Thanks






Offline duma

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Re: finding ph of this problem
« Reply #1 on: November 02, 2014, 09:08:45 PM »
This is my guess

0.016724 mol AA -


0.05011 x 0.1101 = 0.00551711 mol Na OH

ph = 4.757 + Log ( 0.00551711/0.016724)

ph = 4.27

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Re: finding ph of this problem
« Reply #2 on: November 03, 2014, 03:09:13 AM »
Buffer contains an acid and a conjugate base. What is the acid here, what is its conjugate base?
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