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Topic: Ice/Lqd Eq question  (Read 1452 times)

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Offline Clanouper

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Ice/Lqd Eq question
« on: November 07, 2014, 03:10:05 AM »
Correct statements about samples of ice and liquid water at 0 degrees Celsius include which of the following?

I. Molecules in ice and liquid water have the same KE
II. Liquid water has a greater entropy than ice/
III. Liquid water has a greater potential energy than ice.

Apparently, all I, II, III are right. I thought at 0 degrees, both phases are at equilibrium so entropy is equal on both sides. Also, shouldn't PE=KE at equilibrium?

Offline mjc123

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Re: Ice/Lqd Eq question
« Reply #1 on: November 07, 2014, 04:36:27 AM »
Quote
Also, shouldn't PE=KE at equilibrium?
No, why?
At the same temperature the average KE of the molecules is the same in each phase (that is what temperature is).
Quote
I thought at 0 degrees, both phases are at equilibrium so entropy is equal on both sides.
At equilibrium Gibbs free energy is equal: ΔG = ΔH - TΔS = 0.
The liquid has higher potential energy (represented by the enthalpy of fusion) and higher entropy than the solid. They are in equilibrium at a temperature determined by ΔH = TΔS.

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