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Topic: Gas laws; doubling unknown pressure  (Read 4913 times)

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LunaMD

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Gas laws; doubling unknown pressure
« on: April 04, 2006, 05:21:37 PM »
 :-[
These two problems are not making any sense to me.

1. The pressure on a 3.00L sample of gas is doubled, its absolute temperature(K) is increased by 50%, what is its final volume?

I know that temp is proportional to pressure in Gay lussac's Law but i can't figure out if that is the right law to even use since it doesn't seem like it can solve for volume.

2. If the volume of a 4.00L sample of gas is doubled but its final absolute temperature(K) is then reduced to half of its original value what is the final volume of gas?  

I know that they are mentioning the absolute temperature for a reason I just dont understand the relavence. Neither problem mentions STP. Any help would be great!

Offline Mitch

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Re:Gas laws; doubling unknown pressure
« Reply #1 on: April 04, 2006, 05:25:16 PM »
Can't you use pv=nRT for these questions?
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LunaMD

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Re:Gas laws; doubling unknown pressure
« Reply #2 on: April 04, 2006, 05:27:09 PM »
that is what i pondered but i dont know anything but the volume and of course R

Offline Borek

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Re:Gas laws; doubling unknown pressure
« Reply #3 on: April 04, 2006, 05:48:32 PM »
pV/T = nR = const

in other words

p1V1/T1 = p2V2/T2
« Last Edit: April 04, 2006, 05:51:30 PM by Borek »
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LunaMD

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Re:Gas laws; doubling unknown pressure
« Reply #4 on: April 04, 2006, 06:11:28 PM »
V2=v1(t2/t1) (p1/p2) this is how i am setting it up

what is the origingal temmperature 0K?
is the pressure 1atm and 2atm?

Offline Yggdrasil

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Re:Gas laws; doubling unknown pressure
« Reply #5 on: April 04, 2006, 06:20:19 PM »
You don't need to know the original temperatures and presures, just the ratios between them.  For example, you don't know what P1 and P2 are, but you know that P1/P2 is 1/2.

LunaMD

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Re:Gas laws; doubling unknown pressure
« Reply #6 on: April 04, 2006, 06:31:27 PM »
 ;) Got it. v2= 3.00L(1.5/1)(1/2)=2.25L

thanks a bunch

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