[mmman]

So this question asked me to determine whether this compound was aromatic, antiaromatic, or nonaromatic and also asked how many pi electrons there were. I figure since there are four groups of electrons the carbanion is sp3 hybridized and I think I'm correct because that is what this thread says.

https://www.physicsforums.com/threads/question-regarding-hybridization-of-carbon.256312/

But apparently the lone pair on this carbanion in this specific compound lies in a p-orbital? thus making this carbanion sp2 hybridized? for a total of 8 pi electrons. This makes no sense to me any help would be greatly appreciated.

[Dan]

Please add your image as an attachment or fix the image URL - I can't modify your post to do this myself because it requires a physicsforum login to view.

It sounds like this is a case of conjugation and resonance - maybe start by looking up these concepts.