[Student99]

A 0.094g of CuSO4*5H2O is dissolved and diluted to the mark in a 500.0-mL volumetric flask. A 2.00-mL sample of this solution is transferred to a second 500.0-mL volumetric flask and diluted.
A) What is the molarity of CuSO4 in the final solution? B) To prepare the solution directly, what mass of CuSO4*5H2O would need to be weighed out?
Thanks!

[Hunter2]

Please show first your calculation, then you can get help,if something wrong.

[billnotgatez]

@Student99
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[Student99]

Sorry guys, I forgot to post my calcs:

A) C= 0,094/249,7 = 3,76x10^-4

Molarity = 3,76x10^-4/0,5 = 7,529x10^-4 Mol/L
 
C1xV1=C2V2
7,529x10^-4x0,002=C2x0,5
C2=3,01x10^-6 Mol/L


B) Molarity=(Mass)/(Molecular Massx Volume)
Mass = (3,01x10^-6x249,7x500mL)/(1000 mL) = 3,76x10^-4 g

I'm not sure if my calculations are correct.

[Hunter2]

Yes correct.